Using value in combo box based on Foreign key relationship

  • Hello all,

    I am trying to use the below VBA code for sending an email. I would like to use the data in the DefectCategory combo box to pull the correct data the current record. The issue is that I only have the foreign key id in the combo box and would like the more descriptive field called DefectCatType in the table where the defect categories are listed.

    There are two tables involved in this scenario. dbo.NonConfData and dbo.DefectCategory

    dbo.NonConfData is the table with the combo box that references dbo.DefectCategory

    The line I am having an issue with in vb is stDefect = Me.DefectCategory.Value

    I need to have this display the data in the DefectCatType field of the dbo.DefectCategory table for the record in dbo.NonConfData.

    Please let me know your thoughts on how this can be accomplished.

    Private Sub Command75_Click()

    Dim stId As Integer

    Dim db As Database

    Dim rs As DAO.Recordset

    Dim appOutLook As Outlook.Application

    Dim MailOutLook As Outlook.MailItem

    Dim stText As String

    Dim stDefect As String

    '==Save the current record

    If Me.Dirty Then Me.Dirty = False

    Set appOutLook = CreateObject("Outlook.Application")

    Set MailOutLook = appOutLook.CreateItem(olMailItem)

    stId = Me.Id

    stDefect = Me.DefectCategory.Value

    stText = "NonConformance Generated IR #" & stId & Chr$(13) & _

    Chr$(13) & "Defect Category:" & stDefect

    With MailOutLook

    .BodyFormat = olFormatRichText

    .To = "KEITH@COMPANY.com"

    ''.cc = ""

    ''.bcc = ""

    .Subject = "NonConformance Generated IR #" & stId

    .HTMLBody = stText

    .Send

    End With

    End Sub

    Below are my table definitions

    -- Create CaseData Table

    CREATE TABLE dbo.NonConfData

    (

    Id INT IDENTITY(100,1)

    ,CaseDate DATE NOT NULL Default GetDate()

    ,Creator INT NOT NULL

    ,ProducedBy INT NOT NULL

    ,DefectCategory INT NOT NULL

    ,Quantity Decimal(7,2) Default(1.00) NOT NULL

    ,DispositionAuthority VARCHAR (50)

    ,NonConfDetails NVARCHAR(MAX) NOT NULL

    ,InspectorDetails NVARCHAR(MAX) NOT NULL

    ,IRAttachments VARBINARY(MAX)

    ,CONSTRAINT [PK_ID] PRIMARY KEY CLUSTERED

    (

    [ID] ASC

    )WITH

    (

    PAD_INDEX = OFF

    , STATISTICS_NORECOMPUTE = OFF

    , IGNORE_DUP_KEY = OFF

    , ALLOW_ROW_LOCKS = ON

    , ALLOW_PAGE_LOCKS = ON

    ) ON [PRIMARY]

    ) ON [PRIMARY]

    GO

    --Create the Defect Category table

    CREATE TABLE dbo.DefectCategory

    (

    ID INT IDENTITY(1,1) NOT NULL

    ,DefectCatType VARCHAR (25) NOT NULL

    ,DateStamp Date Default GetDate() NOT NULL

    ,CONSTRAINT [PK_DefectID] PRIMARY KEY CLUSTERED

    (

    [ID] ASC

    )WITH

    (

    PAD_INDEX = OFF

    , STATISTICS_NORECOMPUTE = OFF

    , IGNORE_DUP_KEY = OFF

    , ALLOW_ROW_LOCKS = ON

    , ALLOW_PAGE_LOCKS = ON

    ) ON [PRIMARY]

    ) ON [PRIMARY];

    GO

    --Add the foreign key constraint to the NonConfData table and DefectCategory table to establish a relationship

    ALTER TABLE dbo.NonConfData WITH CHECK ADD CONSTRAINT FK_DefectCategory_DefectCatType FOREIGN KEY(DefectCategory)

    REFERENCES dbo.DefectCategory (ID)

    GO

  • If you want to display the content of the combo box control, then you need to use the syntax that chooses the correct column in the combo box row properties. It should look something like:stDefect = Me.DefectCategory.Column(X)where X is the column number where the Defect Category is displayed. Note that the columns numbering begins with 0, so in many cases it would be Column(1).

    Wendell
    Colorful Colorado
    You can't see the view if you don't climb the mountain!

  • Thanks for the reply Wendel. I did try your suggestion but received the error message Method or Data Member not found. I also attached a print screen.

    do you think I'm missing a reference?

  • Disregard my last message. I changed Me.DefectCategory to Me.Combo45.Column(1) and it worked.

    Thanks for that idea.

  • kwoznica (8/28/2013)


    Disregard my last message. I changed Me.DefectCategory to Me.Combo45.Column(1) and it worked.

    Thanks for that idea.

    That indicates the name of your combobox control is Combo45. Your initial code was trying to find a combobox named DefectCategory on your form. If you change the name of Combo45 on the form to DefectCategory, you would be able to use Me.DefectCategory.Column(1).

    ____________
    Just my $0.02 from over here in the cheap seats of the peanut gallery - please adjust for inflation and/or your local currency.

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