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 Posted Thursday, September 16, 2010 10:15 PM
 SSCommitted Group: General Forum Members Last Login: Monday, February 17, 2014 8:01 AM Points: 1,682, Visits: 446
Post #987876
 Posted Thursday, September 16, 2010 11:25 PM
 UDP Broadcaster Group: General Forum Members Last Login: Thursday, November 21, 2013 11:33 PM Points: 1,481, Visits: 1,959
 Nice question. Though the explanation isnt entirely accurate. Its not rounded, its truncated. If the question had been, lets say declare @r decimal(5,2)set @r= round(5/3.2,1,3)select @rThen we would get 1.5 wheras a round would have given us 1.6 (change last parameter in Round to 0... or remove it all together).
Post #987894
 Posted Thursday, September 16, 2010 11:57 PM
 SSC-Insane Group: General Forum Members Last Login: Today @ 9:30 AM Points: 20,195, Visits: 13,715
 thanks for the question Jason AKA CirqueDeSQLeilI have given a name to my pain...MCM SQL ServerSQL RNNRPosting Performance Based Questions - Gail ShawPosting Data Etiquette - Jeff ModenHidden RBAR - Jeff ModenVLFs and the Tran Log - Kimberly Tripp
Post #987902
 Posted Friday, September 17, 2010 2:14 AM
 Ten Centuries Group: General Forum Members Last Login: Wednesday, February 05, 2014 4:11 AM Points: 1,289, Visits: 1,300
 tommyh (9/16/2010)Nice question. Though the explanation isnt entirely accurate. Its not rounded, its truncated. If the question had been, lets say declare @r decimal(5,2)set @r= round(5/3.2,1,3)select @rThen we would get 1.5 wheras a round would have given us 1.6 (change last parameter in Round to 0... or remove it all together).Right, the 3rd parameter of round is the most important one. It's value 3 is not typical but greater than zero. See, understand, learn, try, use efficient© Dr.Plch
Post #987963
 Posted Friday, September 17, 2010 2:54 AM
 SSChampion Group: General Forum Members Last Login: Today @ 8:20 AM Points: 11,837, Visits: 8,786
 Good question, but a real easy one since all the rounding questions of Hugo Kornelis. It would've been more a challenge if you used 3.2 or 3.0, as someone already suggested in this thread. How to post forum questions.Need an answer? No, you need a question.What’s the deal with Excel & SSIS?Member of LinkedIn. My blog at LessThanDot. MCSA SQL Server 2012 - MCSE Business Intelligence
Post #987989
 Posted Friday, September 17, 2010 3:57 AM
 Ten Centuries Group: General Forum Members Last Login: Thursday, January 24, 2013 9:59 PM Points: 1,354, Visits: 1,299
 I got it right but hesitated to click the submit button. It was too easy and I was looking for the tricky part of the question. I've been bitten by so many QOTDs with an obscure typo or something else tricky.
Post #988041
 Posted Friday, September 17, 2010 7:17 AM
 SSCrazy Group: General Forum Members Last Login: Monday, March 03, 2014 2:19 PM Points: 2,795, Visits: 2,535
 Good question. Round is a function with a few gotchas that it is important to know about and understand. Thanks.
Post #988146
 Posted Friday, September 17, 2010 7:29 AM
 SSCommitted Group: General Forum Members Last Login: Yesterday @ 7:02 AM Points: 1,835, Visits: 1,821
 cengland0 (9/17/2010)... I've been bitten by so many QOTDs with an obscure typo or something else tricky.I like composing questions that are on the tricky side. Must be because of all my bad experiences with certification exams.If it's of any consolation, the editors here do have a limit to what they will tolerate for trick questions. I submitted one a few months ago that never got published.I get it. The QOTDs are more about the learning experience than the certification experience.I'm working on one now that's a little more tame...
Post #988169
 Posted Saturday, September 18, 2010 6:15 PM
 Old Hand Group: General Forum Members Last Login: Saturday, October 19, 2013 12:40 PM Points: 361, Visits: 508
 The hardest part of the question was figuring out what is the result of 5/3.1IMHO the point of the question would make more sense if it had been changed to 5/3.0 as the result of the function would actually be affected by the third parameter of the ROUND function unlike in this question.To illustrate:select Example = 'Your example' ,input_data = '5/3.1' ,Truncation = ROUND(1.612903, 1, 1) -- 1.600000 ,Rounding = ROUND(1.612903, 1, 0) -- 1.600000 union allselect 'Better example' ,'5/3.0' ,ROUND(1.666666,1,1) -- 1.600000 ,ROUND(1.666666,1,0) -- 1.700000Example input_data Truncation Rounding-------------- ---------- ------------ ----------Your example 5/3.1 1.600000 1.600000Better example 5/3.0 1.600000 1.700000Regards,Hrvoje Piasevoli Hrvoje Piasevoli
Post #988818
 Posted Sunday, September 19, 2010 7:41 PM
 SSCommitted Group: General Forum Members Last Login: Tuesday, January 21, 2014 8:55 AM Points: 1,520, Visits: 3,035
 honza.mf (9/17/2010)tommyh (9/16/2010)Nice question. Though the explanation isnt entirely accurate. Its not rounded, its truncated. If the question had been, lets say declare @r decimal(5,2)set @r= round(5/3.2,1,3)select @rThen we would get 1.5 wheras a round would have given us 1.6 (change last parameter in Round to 0... or remove it all together).Right, the 3rd parameter of round is the most important one. It's value 3 is not typical but greater than zero.Just to be picky, it's not because the third parameter is greater than zero, but because it is not equal to zero. Here's the entry in BOL for SQL 2005: Syntax ROUND ( numeric_expression , length [ ,function ] ) Argumentsnumeric_expressionIs an expression of the exact numeric or approximate numeric data type category, except for the bit data type.length Is the precision to which numeric_expression is to be rounded. length must be tinyint, smallint, or int. When length is a positive number, numeric_expression is rounded to the number of decimal positions specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified by length.function Is the type of operation to perform. function must be tinyint, smallint, or int. When function is omitted or has a value of 0 (default), numeric_expression is rounded. When a value other than 0 is specified, numeric_expression is truncated.
Post #989059

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