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Find Min of the Two columns when multiplied and Grouped Expand / Collapse
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Posted Wednesday, July 28, 2010 5:23 AM
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Hi,

I have a table which contain the data as follows,

ID first * sec GroupID vid
1 1 2 16 122
3 2 1 16 122
2 3 1 8 33
4 1 5 16 12
5 1 6 16 1

Here I want to get the minimum of the multiples of the column's(first&sec)
that should be grouped with GroupID.For example the result will be


ID first sec GroupID vid

1 2 2 16 122

2 3 1 8 33


Can any one help me out of this?It is very urgent...


Regards

Varun R
Post #959950
Posted Wednesday, July 28, 2010 5:49 AM
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Hi Varun,

please go through this code. i hope this helps you to get the answers..

SELECT a3.*
FROM (SELECT a.GroupID, MIN(MULTICOLUMN)MULTICOLUMN
FROM (SELECT ID, [FIRST] * SEC MULTICOLUMN, GROUPID FROM SAMPLE_TEST)a
JOIN SAMPLE_TEST b On a.ID = b.ID
GROUP BY a.GroupID
) a1
JOIN (SELECT ID, [FIRST] * SEC MULTICOLUMN, GROUPID FROM SAMPLE_TEST) a2 On a1.GroupID = a2.GroupID AND a1.MULTICOLUMN = a2.MULTICOLUMN
JOIN SAMPLE_TEST a3 On a2.ID = a3.ID

Ini your sample, for the ID value 1 & 3 belongs to same groupID "16" and the multiple for Column first&sec is same. so you would be getting 2 rows for the same groupID 16.

If the query has to be changed bit, let me know i can help you in getting the result.

All the best,
Vijay Vasudevan
Post #959958
Posted Wednesday, July 28, 2010 5:56 AM
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select id,first * sec as dd, sec, groupid, vid from MinMultiplecolumn order by dd
Post #959963
Posted Wednesday, July 28, 2010 6:09 AM


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There are many different ways to write a query to do this, here's a popular one:

DECLARE @SampleData
TABLE (
id INTEGER NOT NULL,
first INTEGER NOT NULL,
sec INTEGER NOT NULL,
group_id INTEGER NOT NULL,
vid INTEGER NOT NULL,

PRIMARY KEY CLUSTERED (id)
);

INSERT @SampleData
VALUES (1, 1, 2, 16, 122),
(3, 2, 1, 16, 122),
(2, 3, 1, 08, 033),
(4, 1, 5, 16, 012),
(5, 1, 6, 16, 001);

SELECT  *
FROM (
SELECT *,
row_num =
ROW_NUMBER() OVER (
PARTITION BY S.group_id
ORDER BY S.first * S.sec ASC)
FROM @SampleData S
) S
WHERE S.row_num = 1;





Paul White
SQL Server MVP
SQLblog.com
@SQL_Kiwi
Post #959969
Posted Wednesday, July 28, 2010 6:12 AM
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your idea is good paul.. Thanks dude..

I got a chance to learn new method today!! :)
Post #959970
Posted Wednesday, July 28, 2010 6:20 AM


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But my favourite would probably be this:
DECLARE @SampleData
TABLE (
id INTEGER NOT NULL,
first INTEGER NOT NULL,
sec INTEGER NOT NULL,
group_id INTEGER NOT NULL,
vid INTEGER NOT NULL,
computed AS ISNULL(first * sec, 0)

PRIMARY KEY CLUSTERED (id)
);

INSERT @SampleData
VALUES (1, 1, 2, 16, 122),
(3, 2, 1, 16, 122),
(2, 3, 1, 08, 033),
(4, 1, 5, 16, 012),
(5, 1, 6, 16, 001);

SELECT  S.id, S.group_id, S.computed
FROM @SampleData S
WHERE S.computed =
(
SELECT MIN(S2.computed)
FROM @SampleData S2
WHERE S2.group_id = S.group_id
);

The computed column in the sample table is required to make this work best, but it does not need to be persisted or indexed, so it only really exists in the metadata.

This is a workaround for a limitation in the query optimiser, which might not be necessary in future versions.

One benefit of the computed column (aside from needing no storage space) is that you can create statistics on it. Or at least you could on a real table - the table variable I used for the demo does not support statistics.




Paul White
SQL Server MVP
SQLblog.com
@SQL_Kiwi
Post #959979
Posted Wednesday, July 28, 2010 6:30 AM
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Dear paulwhite,


Thanks for this wonderful solution...Keep it up..Thanks my dear friends for showing interest in answering my question...(For all)







Regards
varun R




Post #959983
Posted Wednesday, July 28, 2010 6:56 AM


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You're welcome.



Paul White
SQL Server MVP
SQLblog.com
@SQL_Kiwi
Post #960000
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