Click here to monitor SSC
SQLServerCentral is supported by Red Gate Software Ltd.
 
Log in  ::  Register  ::  Not logged in
 
 
 
        
Home       Members    Calendar    Who's On


Add to briefcase 123»»»

How can we calculate Age of employee? Expand / Collapse
Author
Message
Posted Sunday, May 10, 2009 10:52 PM


SSC Veteran

SSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC Veteran

Group: General Forum Members
Last Login: Wednesday, July 16, 2014 4:48 AM
Points: 279, Visits: 1,201
Here I have used some queries but i unable to get a exact solution...
Please try else Am I Correct?

My quires:

SELECT EMP_CODE,DATE_OF_BIRTH ,
DATEDIFF(DD,DATE_OF_BIRTH,GETDATE())/365 AS AGE
FROM EMP_MST










Many Thanks!
S.saravanan
“I am a slow walker, but I never walk backwards-
Abraham Lincoln”
Post #713840
Posted Monday, May 11, 2009 12:27 AM
Ten Centuries

Ten CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen Centuries

Group: General Forum Members
Last Login: Thursday, April 19, 2012 10:25 PM
Points: 1,231, Visits: 3,483
Hi,

Your output gives only the days,
The age may come in the format of years months and days like 34 years 10Months and 15 days

ARUN SAS
Post #713858
Posted Monday, May 11, 2009 12:32 AM


SSC Veteran

SSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC Veteran

Group: General Forum Members
Last Login: Wednesday, July 16, 2014 4:48 AM
Points: 279, Visits: 1,201
Ok thanks for replay...

Tell me a another way to fetch the exact age of Different Date...


Many Thanks!
S.saravanan
“I am a slow walker, but I never walk backwards-
Abraham Lincoln”
Post #713862
Posted Monday, May 11, 2009 1:16 AM


Old Hand

Old HandOld HandOld HandOld HandOld HandOld HandOld HandOld Hand

Group: General Forum Members
Last Login: Wednesday, October 17, 2012 10:33 AM
Points: 390, Visits: 405
Hi,
you can try this
select EMP_CODE,DATE_OF_BIRTH ,DATEDIFF(DD,DATE_OF_BIRTH,getdate())/365 as years,(DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365)/30 as months,
DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365%30 as days
from EMP_MST where accountid=4

Hitendra
Post #713886
Posted Monday, May 11, 2009 1:16 AM


Old Hand

Old HandOld HandOld HandOld HandOld HandOld HandOld HandOld Hand

Group: General Forum Members
Last Login: Wednesday, October 17, 2012 10:33 AM
Points: 390, Visits: 405
Hi,
you can try this
select EMP_CODE,DATE_OF_BIRTH ,DATEDIFF(DD,DATE_OF_BIRTH,getdate())/365 as years,(DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365)/30 as months,
DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365%30 as days
from EMP_MST where accountid=4

Hitendra
Post #713887
Posted Monday, May 11, 2009 1:16 AM


Old Hand

Old HandOld HandOld HandOld HandOld HandOld HandOld HandOld Hand

Group: General Forum Members
Last Login: Wednesday, October 17, 2012 10:33 AM
Points: 390, Visits: 405
Hi,
you can try this
select EMP_CODE,DATE_OF_BIRTH ,DATEDIFF(DD,DATE_OF_BIRTH,getdate())/365 as years,(DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365)/30 as months,
DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365%30 as days
from EMP_MST where accountid=4

Hitendra
Post #713888
Posted Monday, May 11, 2009 2:11 AM
Ten Centuries

Ten CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen CenturiesTen Centuries

Group: General Forum Members
Last Login: Thursday, April 19, 2012 10:25 PM
Points: 1,231, Visits: 3,483
t.hitendra (5/11/2009)
Hi,
you can try this
select EMP_CODE,DATE_OF_BIRTH ,DATEDIFF(DD,DATE_OF_BIRTH,getdate())/365 as years,(DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365)/30 as months,
DATEDIFF(DD,DATE_OF_BIRTH,getdate())%365%30 as days
from EMP_MST where accountid=4

Hitendra


Hi,

create the function like

CREATE FUNCTION AGE_ASOF_NOW (@EMP_DOB DATETIME,@curr_dt datetime)
returns varchar(1000)
AS
BEGIN
declare @AGE_ASOF_NOW varchar(100)
declare @DDIFF int
select @DDIFF = datediff(DAY,@EMP_DOB,@curr_dt)
select @AGE_ASOF_NOW = cast((@DDIFF/365)as varchar(4))+' Years '+ cast((@DDIFF%365)/30 as varchar(3))+' Months '+ cast((@DDIFF%365)%30 as varchar(3))+' Days '
return @AGE_ASOF_NOW
END

and call this function in the select statement like

select Dbo.AGE_ASOF_NOW (DATE_OF_BIRTH,getdate())

ARUN SAS
Post #713908
Posted Wednesday, May 13, 2009 8:13 PM


SSCommitted

SSCommittedSSCommittedSSCommittedSSCommittedSSCommittedSSCommittedSSCommittedSSCommitted

Group: General Forum Members
Last Login: Sunday, April 27, 2014 6:26 AM
Points: 1,521, Visits: 3,036
Please be careful using ANY advice from an open forum such as this one without testing it first. The algorithms offered so far are severely lacking in accuracy. Although as schoolchildren, we learned that there are 365 days in a year, most of us would agree that because of the nature of the rules for leap years, we cannot use either 365 or 365.25 as an accurate divisor. And, of course, you don't believe that every month has 30 days.

I do appreciate the opportunity your request and the interim responses gave me to work up what I now believe to be an accurate script for returning an age in years, months and days. As has been suggested, it would probably be best implemented as a UDF (user defined function).

Oh. One more thing. Despite my confidence in this code, you must be sure of it before using it. Test it with as many weird combinations of @Today and @DOB as you can to prove out its accuracy.
Declare @DOB smallDatetime
,@Today smallDatetime
,@AgeYears int
,@AgePlusMonths int
,@AgePlusDays int
,@LastBD datetime
,@LastMonthBD datetime

--======================--
set @DoB = '20040228'
set @Today = '20080229'
--======================--

select
@AgeYears
= year(@today)-year(@dob)
- case when month(@today) < month(@dob)
or (month(@today) = month(@dob) and day(@today) < day(@dob))
then 1
else 0
end
,@LastBD = dateadd(year,@AgeYears,@Dob)
,@AgePlusMonths = datediff(month, @LastBD, @Today)
- case when month(@today) <= month(@LastBD) and day(@today) < day(@LastBD)
then 1
else 0
end
- case when month(@dob) = 2 and day(@dob) = 29
then 1
else 0
end
,@LastMonthBD = dateadd(month,@AgePlusMonths,@LastBD)
,@AgePlusDays = datediff(day, @LastMonthBD, @Today)

Select @today as today
,@DoB DoB
,@LastBD as LastBD
,@LastMonthBD as LastMonthBD
,@AgeYears AgeYears
,@AgePlusMonths As AgePlusMonths
,@AgePlusDays as AgePlusDays

Post #716606
Posted Thursday, May 14, 2009 2:12 AM
SSC Veteran

SSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC VeteranSSC Veteran

Group: General Forum Members
Last Login: Today @ 3:32 AM
Points: 246, Visits: 2,039



declare @birthday datetime
declare @ToDate datetime
DECLARE @smonth TINYINT, @sday TINYINT, @syear SMALLINT
DECLARE @emonth TINYINT, @eday TINYINT, @eyear SMALLINT
DECLARE @months TINYINT, @days TINYINT, @years SMALLINT
DECLARE @tdate SMALLDATETIME


set @birthday = '15 feb 1969'
--set @retireage = 65
set @birthday = @birthday--getdate()

set @ToDate = getdate()--dateadd(year, +@retireage, @birthday)

--print @ToDate

SET @smonth = MONTH(@birthday)
SET @sday = DAY(@birthday)
SET @syear = YEAR(@birthday)
SET @emonth = MONTH(@ToDate)
SET @eday = DAY(@ToDate)
SET @eyear = YEAR(@ToDate)
SET @years = @eyear - @syear
SET @months = 0
SET @days = 0
IF (@emonth >= @smonth)
SET @months = @emonth - @smonth
ELSE
BEGIN
SET @years = @years - 1
SET @months = @emonth + 12 - @smonth
END
IF (@eday >= @sday)
SET @days = @eday - @sday
ELSE
BEGIN
IF (@months > 0)
SET @months = @months - 1
ELSE
BEGIN
SET @years = @years - 1
SET @months = @months + 11
END
SET @tdate = DATEADD(yy,@years,@birthday)
SET @tdate = DATEADD(m,@months,@tdate)
SET @days = DATEDIFF(d,@tdate,@ToDate)
END





print 'Accurate Age: (' +convert(varchar(11), @ToDate, 113) + ') ' +
convert(varchar(3), @years) + ' Years ' + convert(varchar(3), @months) + ' Months ' + convert(varchar(3), @days) + ' Days ' +
substring(CONVERT(VARCHAR(8),DATEADD(ss,datediff(second, @birthday, @todate),0),108), 1, 2) + ' Hours ' + substring(CONVERT(VARCHAR(8),DATEADD(ss,datediff(second, @birthday, @todate),0),108), 4, 2) + ' Minutes ' + substring(CONVERT(VARCHAR(8),DATEADD(ss,datediff(second, @birthday, @todate),0),108), 7, 2) + ' Seconds '

Post #716708
Posted Thursday, May 14, 2009 12:19 PM
SSC Eights!

SSC Eights!SSC Eights!SSC Eights!SSC Eights!SSC Eights!SSC Eights!SSC Eights!SSC Eights!

Group: General Forum Members
Last Login: Thursday, July 24, 2014 8:41 AM
Points: 861, Visits: 2,357
+1 on testing with weird dates (both date of birth and as-of dates).

You must also know your business rule for leap day babies in non-leap-years. A version of what I use (not cleaned up! Please excuse bad table names, bad capitalization, and so on) follows.

Note there is a test query and small selection of interesting test cases that can be run as required in the comments at the beginning of the function.

create function dbo.ddfn_UT_AgeInYears
(
@START_DATE datetime,
@END_DATE datetime
)
returns int
as
/*

Original code came from http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=74462
Original name F_AGE_IN_YEARS.

Updated 20080109 PH - comments updated.
Updated 20080423 PH - comments updated.

Function ddfn_UT_AgeInYears computes Age in years.

Input parameters @START_DATE and @END_DATE
are required. If either or both parameters
are null, the function returns null.
if @START_DATE midnight is greater than
@END_DATE midnight, the function returns NULL.

i.e. SELECT dbo.ddfn_UT_AgeInYears('1988-02-29','2007-02-28')


Age is defined as the number of anniversary dates
reached or passed from @START_DATE through @END_DATE.

Age is calculated based on midnight (00:00:00.000)
of parameters @START_DATE and @END_DATE.
Time of day is not used in the calculation.

NULL is returned when the @END_DATE is earlier
than the @START_DATE.

For example, someone born 2000-02-15
would be 5 years old on 2006-02-14,
but 6 years old on 2006-02-15.

Someone born on Feb 29 would be a year
older on Feb 28 in non-leap years, but
would be a year older on Feb 29 in leap years.

Function is valid for entire range of datetime
values from 1753-01-01 00:00:00.000 to
9999-12-31 23:59:59.997.

Quick test code:
declare @strSql varchar(8000)
set @strSql = ''
SET @strSql = 'select '
+ 'DOB AS BirthDate, '
+ 'AsOfDt AS AsOfDate, '
+ 'database.dbo.ddfn_UT_AgeInYears(DOB,AsOfDt) AS UT_AgeInYears'
+ ' FROM '
+ ' (SELECT ''2004-02-29'' AS DOB, ''2004-02-28'' AS AsOfDt'
+ ' union all SELECT ''2004-02-29'' AS DOB, ''2004-02-29'' AS AsOfDt'
+ ' union all SELECT ''2004-02-29'' AS DOB, ''2004-03-01'' AS AsOfDt'
+ ' union all SELECT '''' AS DOB, '''' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2007-02-27'' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2007-02-28'' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2007-03-01'' AS AsOfDt'
+ ' union all SELECT '''' AS DOB, '''' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2008-02-28'' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2008-02-29'' AS AsOfDt'
+ ' union all SELECT ''1988-02-29'' AS DOB, ''2008-03-01'' AS AsOfDt'
+ ') HardCodeDateList'
exec (@strSQL)


*/

begin

declare @AGE_IN_YEARS int

-- Start out by setting the times to midnight.
select @START_DATE = dateadd(dd,datediff(dd,0,@START_DATE),0),
@END_DATE = dateadd(dd,datediff(dd,0,@END_DATE),0)

if @START_DATE > @END_DATE
begin
return null
end

select
@AGE_IN_YEARS =
datediff(yy,StartDateYearStart,EndDateYearStart) +
-- Subtract 1 if anniversary date is after end date
case
when AnniversaryThisYear <= @END_DATE
then 0
else -1
end
from
(
select AnniversaryThisYear =
dateadd(yy,datediff(yy,StartDateYearStart,EndDateYearStart),@START_DATE),
StartDateYearStart,
EndDateYearStart
from
(
select StartDateYearStart =
dateadd(yy,datediff(yy,0,@START_DATE),0),
EndDateYearStart =
dateadd(yy,datediff(yy,0,@END_DATE),0)
) aa
) a

return @AGE_IN_YEARS

end


Post #717262
« Prev Topic | Next Topic »

Add to briefcase 123»»»

Permissions Expand / Collapse