how to create user group logins in SQL server 2005

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how to create user group logins in SQL server 2005

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rolyn_jimenez

Posted Thursday, June 26, 2008 12:17 AM

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I just want to create a group login then all the users i will create i'l just add them to the group login i created.

can you please help how to create group login and how to input the users login in the group login created? thanx for advance

Post #523889

Jonathan Kehayias

Posted Friday, June 27, 2008 8:36 PM

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Generally speaking this is accomplished with an Active Directory Domain Users Group. You add the AD Group to SQL Server as a Login, and then grant the correct rights to the AD Group Login in SQL. Then to add people to SQL with the Group rights, you simply add them to the Group in Active Directory. You also get the added benefits of the AD GPO's being enforced for the account so you don't have to worry about password expiration or complexity rules since this is enforced by AD.

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Post #525411

sm1st2002

Posted Monday, February 25, 2013 9:53 AM

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Hi,

I'm using SQL Server 2005 and when i right-click on Security, I see the following options:

User, Database role, Application role, Schema.

Which is the correct option for me to choose when creating a new Group?

Thanks.

Post #1423673

Lowell

Posted Monday, February 25, 2013 10:00 AM

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you choose New Login, and then use the find object to find a windows group....once you are in there, it becomes more clear:

Lowell

--There is no spoon, and there's no default ORDER BY in sql server either.
Actually, Common Sense is so rare, it should be considered a Superpower. --my son

Post #1423676

sm1st2002

Posted Monday, February 25, 2013 4:25 PM

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Hi there,

Thanks very much, and the screen shots are very useful? I also got abit confused in where / how I create a new login, as when I right-clicked on Security I was displayed the options as mentioned previously, nothing as straight forward as if to say 'new Login'...but I will play about with the system and let u know if I still can't create a group!

Thanks,

Post #1423813

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