Query

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Rajani Poduval

Posted Saturday, May 17, 2008 11:59 PM

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Last Login: Sunday, May 25, 2008 11:04 PM
Points: 30, Visits: 11

Hi there Gurus!

I thought I was a naive beyond imagination 'cos I completely missed the purpose of that query!
Looks like something framed on a particularly boring afternoon :)

We need better than that if we are to learn!

The naïveté

Post #502586

WilliamD-

Posted Tuesday, May 20, 2008 4:14 AM

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Hi There,

I agree that the query would work, but only on the premise that only one of the tables had the column customerid. To say that any of the two tables could have the customerid would require having an alias to resolve the column.

My 2 cents

:)

Regards,

WilliamD

Post #503430

James Goodwin

Posted Friday, May 23, 2008 8:56 AM

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I don't think that the fact that the query compiles is a bug per se. It compiles because subqueries must have access to their parent in order to create correlated queries. The compiler can't assume what that correlation is going to look like so if it can resolve the name it will. Think of:

select Count(*)
FROM ClientTable
where Exists (SELECT * FROM OrderTable where PKClientID = FKClientID)

Now, while I consider it bad to have different names for the same information, I 've seen this type of design. The Compiler must be able to compile the above because it is valid. Therefore it also must be able to compile the syntactically correct, but bizarre:
select * from ClientTable, Contracts
Where clientid in (select contractclientid where overdue > 30)

As far as the compiler is concerned as long as the names contractclientid and overdue are resolvable then it is a syntactically valid statement.
--
JimFive

Post #505936

malathi.nicegirl

Posted Tuesday, July 08, 2008 5:27 AM

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Query

What will happen if following query get executed:

select CategoryID, Quantity, Price
from Customer c, SalesOrderDetail sod
where sod.clientid in (select customerid where pricingplan='X')

In this Query options nothing was spoken about pricingplan column.
If pricingplan column is not part of either of the tables then the query will end up in Error. Why not the Third option is right answer for this Question in this scenario?? :)

Post #529906

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