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 Posted Tuesday, February 05, 2008 7:11 AM
 SSCertifiable Group: General Forum Members Last Login: 2 days ago @ 7:32 AM Points: 6,274, Visits: 12,089
 DECLARE @TheDate DATETIMESET @TheDate = '2008-02-05 23:59:59.997'SELECT @TheDate SELECT CAST(CAST(@TheDate-0.5000000385803 AS INT) AS DATETIME) SET @TheDate = '2008-02-05 00:00:00.000'SELECT CAST(CAST(@TheDate-0.5000000385803 AS INT) AS DATETIME);)We're still on 2K, could be decades before we see 2K8 “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps
Post #451621
 Posted Tuesday, February 05, 2008 9:00 AM
 Ten Centuries Group: General Forum Members Last Login: Tuesday, December 03, 2013 3:46 PM Points: 1,318, Visits: 7,143
 it doesn't wait until noon to start rounding up...DECLARE @TheDate DATETIMESET @TheDate = '2008-02-05 11:59:59.993'SELECT @TheDate SELECT CAST(@TheDate AS INT) SELECT CAST(CAST(@TheDate AS INT) AS DATETIME) SET @TheDate = '2008-02-05 11:59:59.997'SELECT @TheDateSELECT CAST(@TheDate AS INT) SELECT CAST(CAST(@TheDate AS INT) AS DATETIME) bc
Post #451699
 Posted Tuesday, February 05, 2008 9:25 AM
 SSCertifiable Group: General Forum Members Last Login: 2 days ago @ 7:32 AM Points: 6,274, Visits: 12,089
 DECLARE @TheDate DATETIME, @HalfDayAndaBit DECIMAL (14,13)SET @HalfDayAndaBit = 0.5000000385803SET @TheDate = '2008-02-05 11:59:59.993'SELECT @TheDate SELECT CAST(@TheDate-@HalfDayAndaBit AS INT) SELECT CAST(CAST(@TheDate-@HalfDayAndaBit AS INT) AS DATETIME) SET @TheDate = '2008-02-05 11:59:59.997'SELECT @TheDateSELECT CAST(@TheDate-@HalfDayAndaBit AS INT) SELECT CAST(CAST(@TheDate-@HalfDayAndaBit AS INT) AS DATETIME) That's where the 'AndaBit' comes in. “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps
Post #451719
 Posted Tuesday, February 05, 2008 9:59 AM
 Forum Newbie Group: General Forum Members Last Login: Thursday, July 02, 2009 3:20 PM Points: 1, Visits: 9
 If you don't care about the date coming back as an string. Then this is good solution too.PRINT LEFT(getdate(), 11)
Post #451741
 Posted Tuesday, February 05, 2008 2:24 PM
 SSC-Enthusiastic Group: General Forum Members Last Login: Yesterday @ 7:52 PM Points: 123, Visits: 1,159
 or...Select convert(char(10),getdate(),101)
Post #451899
 Posted Tuesday, February 05, 2008 2:59 PM
 SSC Eights! Group: General Forum Members Last Login: Thursday, December 05, 2013 7:12 AM Points: 859, Visits: 1,641
 Thanks for a helpful article. Good discussion, too!Julie
Post #451913
 Posted Wednesday, February 06, 2008 2:56 AM
 Ten Centuries Group: General Forum Members Last Login: Wednesday, November 13, 2013 8:53 AM Points: 1,342, Visits: 1,969
 James A. Lawrence (2/5/2008)or...Select convert(char(10),getdate(),101)Of course I'd use convert(char(10),getdate(),103)...Which raises a question I haven't found an answer to:Why does America (and nowhere else) write dates in their traditional order, i.e. month/day/year?Everywhere else has a date order which either goes from specific to general (day-month-year) or the reverse (y-m-d). Why does America use a medium-small-large (m-d-y) ordering such that a mechanical 'odometer' would have to update the middle section first, then the left end, then the right end rather than the more logical left-to-right or right-to-left? Derek
Post #452082
 Posted Wednesday, February 06, 2008 7:09 AM
 SSCrazy Group: General Forum Members Last Login: Monday, December 02, 2013 9:20 AM Points: 2,591, Visits: 18,995
 why am I getting times in the result for all of these, when I want only the date portion? ---------------------------------------------------------How best to post your questionHow to post performance problemsTally Table:What it is and how it replaces a loop"stewsterl 80804 (10/16/2009)I guess when you stop and try to understand the solution provided you not only learn, but save yourself some headaches when you need to make any slight changes."
Post #452180
 Posted Wednesday, February 06, 2008 7:13 AM
 SSChasing Mays Group: General Forum Members Last Login: 2 days ago @ 5:59 AM Points: 630, Visits: 334
 That'd be because the data type is dateTIME. If you want just date, convert to SQL 2K8 and use a date only datatype, or as previous example above have done, convert to a char data type with only the date portion being returned.
Post #452182
 Posted Wednesday, February 06, 2008 7:16 AM
 SSCertifiable Group: General Forum Members Last Login: 2 days ago @ 7:32 AM Points: 6,274, Visits: 12,089
 jcrawf02 (2/6/2008)why am I getting times in the result for all of these, when I want only the date portion?Curious - can you post what you've tried, with the results? “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps
Post #452185

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