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 Posted Saturday, September 29, 2007 1:25 PM
 Forum Newbie Group: General Forum Members Last Login: Friday, March 14, 2014 8:04 PM Points: 7, Visits: 7
 DECLARE @MYDECVAR DECIMAL DECLARE @MYINTVAR INT SET @MYDECVAR = 100.123 SET @MYINTVAR = CAST(@MYDECVAR AS INT) SELECT @MYINTVAR CHEERS :) CHANDRA
Post #404461
 Posted Saturday, September 29, 2007 2:15 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 DECLARE @MYDECVAR DECIMAL DECLARE @MYINTVAR INT SET @MYDECVAR = 100.123 SET @MYINTVAR = CAST(@MYDECVAR AS INT) SELECT @MYINTVAR This returns 100, not 100123 as it should.
Post #404465
 Posted Saturday, September 29, 2007 2:37 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 This should do the trick... 100% of the time : DECLARE @Val DECIMAL (11,8) SET @Val = 100.10300100 SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @Val), '.', ''), '0', ' '))), ' ', '0') SET @Val = 0.01 SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @Val), '.', ''), '0', ' '))), ' ', '0') SET @Val = 1 SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @Val), '.', ''), '0', ' '))), ' ', '0') SET @Val = 0010.20301 SELECT REPLACE(RTRIM(LTRIM(REPLACE(REPLACE(CONVERT(VARCHAR(30), @Val), '.', ''), '0', ' '))), ' ', '0')
Post #404471
 Posted Saturday, September 29, 2007 3:56 PM
 SSC-Forever Group: General Forum Members Last Login: Yesterday @ 10:35 PM Points: 42,070, Visits: 39,452
 Why do you think you need the extra overhead of RTRIM/LTRIM when converting Decimal to Varchar? --Jeff Moden"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column." Helpful Links:How to post code problemsHow to post performance problems
Post #404489
 Posted Saturday, September 29, 2007 4:18 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 For dropping leading and trailing 0s from the string. Maybe I just missed the problem altogether... Must be having a bad day or something.
Post #404497
 Posted Saturday, September 29, 2007 4:30 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 Cancel that, I'm having a great day, this is why I came up with this solution : declare @i decimal(10,5) Set @i = 1078.734 PRINT REPLACE(@i,'.','') --What's needed? 107873400 or 1078734 Set @i = 0.034 PRINT REPLACE(@i,'.','') --003400 OR 34? Set @i = 0.0304 PRINT REPLACE(@i,'.','') --003040 OR 304? --Now Jeff, let's see your solution to crap out those leading and trailing 0s.
Post #404502
 Posted Saturday, September 29, 2007 4:38 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 Tomm Carr (9/28/2007)The problem with using the Replace string function is that 10.341 ends up as 1034100 if the numeric is defined with five places. If you want 10.342 to end up as 10341, 10.73 as 1073, 10.733 as 10733, 10.7333 as 107333 and 10.7 as 107, then the best way is to use numeric processes rather than string. The only thing is, you have to define your working number to have enough places to the left to contain the entire value. So your example of storing 10.341 into a variable defined as decimal(5,4) is bogus--it only has one place to the left of the decimal point. So if your value is defined as "decimal(x,y)" then you have to declare a working variable as "decimal(x+y,y)" to contain the entire finished value. ```declare @Original decimal( 10, 5 ), @Working decimal( 15, 5 ), -- 10 + 5 = 15 @Result decimal( 15, 0 ); -- Doesn't need scale, only precision Set @Original = 1078.734; -- This would be, say, an input parameter -- First, make a copy into the working variable capable of handling it. Set @Working = @Original; -- Now set up the loop Set @Result = Floor( @Working ); While @Result < @Working begin Set @Working = @Working * 10; Set @Result = floor( @Working ); end--while select @Result as Result, @Working as Working;```The loop executes one time through for each significant digit to the right of the decimal point -- in this example, three times. The result is 1078734 instead of 107873400. As an aside, does anyone know how to get the old "
" formatting back? This code IFCode shortcut sucks. Sure, the code goes into a nice text field :) but everything is double spaced.       Sorry Tomm, I had missed your post.  Your solution is much much workable than mine.
Post #404504
 Posted Saturday, September 29, 2007 9:06 PM
 SSC-Forever Group: General Forum Members Last Login: Yesterday @ 10:35 PM Points: 42,070, Visits: 39,452
 Did someone say "loop"??? On a single row????? Using a previous example where 5 decimal places are required to be padded with zeros... DECLARE @i DECIMAL(10,5) SET @i = 1078.734 PRINT REPLACE(STR(@i,15,5),'.','') Why do you need a loop???? --Jeff Moden"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column." Helpful Links:How to post code problemsHow to post performance problems
Post #404545
 Posted Saturday, September 29, 2007 9:23 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 So Jeff, how do you solve this version of the problem? declare @i decimal(10,5) Set @i = 1078.734 PRINT REPLACE(@i,'.','') --What's needed? 107873400 or 1078734 Set @i = 0.034 PRINT REPLACE(@i,'.','') --003400 OR 34? Set @i = 0.0304 PRINT REPLACE(@i,'.','') --003040 OR 304?
Post #404557
 Posted Saturday, September 29, 2007 9:24 PM
 SSC-Insane Group: General Forum Members Last Login: Wednesday, April 13, 2016 12:23 AM Points: 20,643, Visits: 9,671
 Jeff as for the loop, I can appreciate a good mathematical solution. I wouldn't use it but I thaught it was neat.
Post #404558

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