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Posted Thursday, April 10, 2014 5:01 AM
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Apologies if this has been discussed before:

I need to calculate a due date from a given start date to exclude weekends and holidays.

Can anyone help?

Many thanks
Post #1560356
Posted Thursday, April 10, 2014 5:33 AM
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Hi Duncan,

you first need to decide which days are weekend by using the datepart function and create a list of every day between the 2 stating which is a weekend. then sum the difference.

Excluding Holidays is more involved as you have to individually update the table to show which days have been holidays which SQL doesn't store.an example using the code below could be:

update #temp
set workdayind = 0
where fulldate = 'Date of holiday'

but you'd need one per holiday.


set dateformat ymd
set datefirst 1
declare @StartDate datetime
declare @endDate datetime

set @StartDate = cast('2014/01/31' as datetime) ---- replace with startdate
set @EndDate = DATEADD(dd, -1, left(getdate(), 11)) ----- replace with endDate


create table #temp
(Fulldate datetime, WorkingDayind tinyint)



Repeat:

set @Startdate = @StartDate + 1

insert into #temp
(Fulldate, WorkingDayind)

select @StartDate,
case when datepart(dw, @StartDate) <= 5 then 1 else 0 end


if @StartDate < @endDate goto Repeat


select SUM(WorkingDayind) from #temp

select * from #temp

drop table #temp

I'm more than open to a simpler way of doing it but this was the only way I could think of at the time.

J
Post #1560370
Posted Thursday, April 10, 2014 6:41 AM
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try this


Declare @start_dte as datetime = '01-Apr-2014'
, @end_dte as datetime = '30-Apr-2014'

Declare @WeekDayTable Table ( colWeekDayID tinyint
, ColWeekDayName varchar(20)
, ColIsWeekEnd bit
)

Declare @HolidayTable Table ( ID int identity(1,1)
, HolidayDt Datetime
)

insert into @WeekDayTable
Select 1,'Sunday' , 0 union all
Select 2,'Monday' , 1 union all
Select 3,'Tuesday' , 1 union all
Select 4,'Wednesday', 1 union all
Select 5,'Thursday' , 1 union all
Select 6,'Friday' , 1 union all
Select 7,'Saturday' , 0;


insert into @HolidayTable
Select '02-Apr-2014';


;With cCalender
AS
(
Select N AS ID, dateadd(dd,N-1,@start_dte) AS CalenderDate
, DATEPART(DW,dateadd(dd,N-1,@start_dte)) as WeekDays
, DATENAME(DW,dateadd(dd,N-1,@start_dte)) as WeekDayName
from
(
Select top 10000 row_number() Over (Order by o.id) as N
from sysObjects o
cross join sysobjects oo
) Tally
Where dateadd(dd,N-1,@start_dte) <= @end_dte
)

select count(*) AS NoOfBussinessDays
from cCalender c
Where Not Exists ( Select 1
From @WeekDayTable w
Where c.WeekDayName = w.ColWeekDayName
And ColIsWeekEnd = 0
)
And Not Exists ( select 1
from @HolidayTable h
where h.HolidayDt = c.CalenderDate
)

Hope it helps
Post #1560396
Posted Thursday, April 10, 2014 7:16 AM
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Thanks for the replies.

I have a calendar table.
When I calculate 20 days from the start date to get my end date.
Then add my hols and weekends to get the new end date it just feels like this might be an endless cycle to get the eventual end date.

Hope I'm making sense.

Thanks in advance


Post #1560415
Posted Friday, April 11, 2014 12:14 AM
Say Hey Kid

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Then add my hols and weekends to get the new end date it just feels like this might be an endless cycle to get the eventual end date.


What exactly you have implemented can you share us the code?
Post #1560713
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