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Posted Wednesday, January 1, 2014 12:25 PM


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The two more significant bits and the least significant bit were how I got it.


Sincerely,
Daniel
Post #1526940
Posted Wednesday, January 1, 2014 9:09 PM
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Required to do Some pen paper work..!!
Nice Question to Start the Year 2014.

Thanks for the question.
Post #1526975
Posted Wednesday, January 1, 2014 10:09 PM
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thanks steve,..... & happy new year to all!
Post #1526978
Posted Thursday, January 2, 2014 2:55 AM
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First, notice 2014 is even, so first and third answer are out because they are odd.
Next, notice the bits that differ in the remaining two answer choices(second bit from the left having value of 512) and see which choice is correct.
Calculate 2014 minus 1024(the leftmost bit value) to see if difference leaves enough to subtract 512. If yes, choose answer with bit on; if no choose answer with bit off. Since the answer is yes, then the 512 bit must be on, so the correct answer is the fourth choice.
Post #1527015
Posted Thursday, January 2, 2014 4:21 AM
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Happy New Year 11111011110 to All!!!!


Post #1527033
Posted Thursday, January 2, 2014 4:28 AM
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Happy New Year to all of you......
Post #1527034
Posted Thursday, January 2, 2014 5:14 AM
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Happy New Year, Everybody!

Hope you are all able to keep your resolutions; I'll try my best to complete mine. One of which is to be more active in the Sql Server community.



---------------
Mel.

It's no fun if it's not complicated.

Post #1527045
Posted Thursday, January 2, 2014 6:52 AM


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Sad that 9%, er 1001%, selected answers that ended in 1!

Thanks for the question.


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Post #1527095
Posted Thursday, January 2, 2014 8:41 AM


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Great question and happy new year!



Everything is awesome!
Post #1527158
Posted Thursday, January 2, 2014 9:18 AM


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Thomas Abraham (1/2/2014)
Sad that 9%, er 1001%, selected answers that ended in 1!

Thanks for the question.


+1010




Jason AKA CirqueDeSQLeil
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Post #1527183
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