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How to create a dropdown list in which one choice will have the two possible values? Expand / Collapse
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Posted Thursday, November 28, 2013 9:36 AM


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Dear sqlservercentral members,

Hello and a pleasant day.

I would like to ask how to create a dropdown list in which one choice will have the two possible values? In the report I am creating for a certain customer, they need to choose between USA and EUROPE, and BOTH of them…the customer who requested the report wants a <BOTH>, USA, EUROPE should appear on the dropdown choice. In my first work, I declare a parameter (the name is @Country) that allows multiple values, so the output of the dropdown is:

(Select All)
USA
EUROPE

But like what I'd said, the customer wants a dropdown like:

<BOTH>
USA
EUROPE

So if the customer selects <BOTH>, it will be both USA and EUROPE.

By the way, here is the query I used:


SELECT * FROM tblInvoice WHERE COUNTRY IN (@Country)


Thank you for any advice that you may give.

Respectfully Yours,
MarkSquall


________________________________
"Listen to advice and accept instruction, and in the end you will be wise." -Proverbs 19:20
Post #1518380
Posted Thursday, November 28, 2013 6:03 PM


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Some choices, which one is best for you will depend on your setup.

First though, Country in (@Country) is misleading as @Country is one value, not a list by the time SQL gets to see it, so changing your WHERE clause to Country = @Country would achieve the same result but make it clear you understand that @Country is a single value...

1. add OR @Country='BOTH' to the query (and use "BOTH" as the value for the "BOTH" label in your dropdown list...
2. change to using Country = ISNULL(NULLIF(@Country,'BOTH'),Country)
3. change your query to use an IF
IF @Country = 'BOTH'
SELECT col1 ,col2, col3 FROM tblInvoice
ELSE
SELECT col1 ,col2, col3 FROM tblInvoice WHERE Country = @Country
4. Filter the data in the report and set the value of the label "BOTH" to USA,EUROPE in the dropdown

I am sure there are other ways also, these are just a few.

I would personally prefer options 3 or 4 but it all depends on your exact situation.



MM


select geometry::STGeomFromWKB(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  • Post #1518425
    Posted Friday, December 6, 2013 9:54 AM


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    Dear mister.magoo,

    Hello to you. Thanks for the advise, I already got it.

    Aside from your tip, I learned something new (still on comprehending but I will get there...just more and more practice I guess) about functions that returns a table and I used this to split the data into a certain delimiter (in this case, the delimiter is a comma).

    Thank you and more power.


    Respectfully Yours,

    MarkSquall


    ________________________________
    "Listen to advice and accept instruction, and in the end you will be wise." -Proverbs 19:20
    Post #1520654
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