Click here to monitor SSC
SQLServerCentral is supported by Red Gate Software Ltd.
 
Log in  ::  Register  ::  Not logged in
 
 
 
        
Home       Members    Calendar    Who's On


Add to briefcase

Adding a min, max and avg column Expand / Collapse
Author
Message
Posted Monday, March 18, 2013 4:11 PM
Forum Newbie

Forum NewbieForum NewbieForum NewbieForum NewbieForum NewbieForum NewbieForum NewbieForum Newbie

Group: General Forum Members
Last Login: Thursday, October 9, 2014 4:27 AM
Points: 1, Visits: 51
I have a table like so.
Table A
[Job Lot] [Job ID] [Child Job ID] [Time Completed] [Order of Jobs Done]
1 11 100 10 Pos 1
1 11 101 20 Pos 2
1 11 103 30 Pos 3
2 12 101 30 Pos 1
2 12 105 10 Pos 3
Each Child Job ID represents a delivery to a particular site like New York, Washington or LA each week.

So I need to work work out say for Child ID 101 what is the average postion . I see in JOB ID 11 it has Child Job ID 100 in POS 2 and in JOB ID 12 it is in POS 1, so the min is POS1 , the max is POS2, and the average is POS 1.5. So what is the spread of CHILD JOB ID and position is the real question , so out of 4 CHILD JOB IDS of say 101 what is the spread, is it always usuallt at postion 1.

For CHILD JOB ID 10 , I want the lowest rank of Position 0 , the highest rank value of Position 3 and the Average vlaue not considering any null values and only divide by number of non null vlaues. In this case the the average rank would be Postion 2.

So I need to add 3 columns to store these values ? How can I do this in one query ? Do I need to pivot the data first ?

SELECT [JOB LOT],[CHILD JOB ID], MIN([ORDER OF JOBS DONE])AS [MIN],MAX([ORDE OF JOBS DONE])AS [MAX]
FROM TABLE A WHERE [ORDER OF JOBS DONE] IS NOT NULL group by [JOB LOT],[ORDER OF JOBS DONE]
Post #1432378
Posted Monday, March 18, 2013 4:56 PM


SSC-Dedicated

SSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-Dedicated

Group: General Forum Members
Last Login: Today @ 12:27 PM
Points: 35,371, Visits: 31,916
Your post is a bit confusing. According to what you posted, the "Child ID 10" is actually in a column called "[Time Completed]".

Take a look at the first link in my signature on how to post readily consumable data so you can get good answers very quickly. If it's not readily consumable data, you might not get coded answers.


--Jeff Moden
"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".

First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column."

(play on words) "Just because you CAN do something in T-SQL, doesn't mean you SHOULDN'T." --22 Aug 2013

Helpful Links:
How to post code problems
How to post performance problems
Post #1432400
Posted Monday, March 18, 2013 6:20 PM


SSC-Dedicated

SSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-DedicatedSSC-Dedicated

Group: Administrators
Last Login: Wednesday, October 22, 2014 12:34 PM
Points: 31,181, Visits: 15,626
As Jeff mentioned, this is confusing. For Job ID 11, I see a 100 as Position 1, not 2. Or am I missing something?








Follow me on Twitter: @way0utwest

Forum Etiquette: How to post data/code on a forum to get the best help
Post #1432421
« Prev Topic | Next Topic »

Add to briefcase

Permissions Expand / Collapse