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Home » Article Discussions » Article Discussions by Author » Discuss Content Posted by Eli Leiba » Casting question
Add to briefcase
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Christian Buettner-167247
Posted Friday, March 15, 2013 1:32 AM
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Good question but the correct answer is "0 " (with 2 trailing spaces), not "0".#

Edit: Add example:
SELECT REPLACE(ISNULL ( CONVERT (char(3),1/9),'*'),' ','<Space>') AS Ret

0<Space><Space>

Best Regards,
Chris Büttner
Post #1431385
okbangas
Posted Friday, March 15, 2013 1:45 AM


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Really easy question, but the explanation puzzles me. As far as I can see it is no implicit conversion, just a pure integer division.


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Post #1431388
Stuart Davies
Posted Friday, March 15, 2013 1:53 AM


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Nice and easy question to end the week on - thanks

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Smart way to ask a question

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Post #1431391
demonfox
Posted Friday, March 15, 2013 1:54 AM
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okbangas (3/15/2013)
Really easy question, but the explanation puzzles me. As far as I can see it is no implicit conversion, just a pure integer division.

+1
0.111111 being counted as 0 , is a round off to integer ..

will that be implicit conversion OP had in mind,0.11111-float to 0 - int?



~ demonfox
___________________________________________________________________
Wondering what I would do next , when I am done with this one
Post #1431392
Carlo Romagnano
Posted Friday, March 15, 2013 2:21 AM


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okbangas (3/15/2013)
Really easy question, but the explanation puzzles me. As far as I can see it is no implicit conversion, just a pure integer division.

+1
Post #1431401
Raghavendra Mudugal
Posted Friday, March 15, 2013 3:31 AM


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ah ... this was soo easy, i just selected the answer in one click.... but selected the wrong one. (interesting read, so far)

ww; Raghu
--
There are only 10 types of people in the world, those who understand binary, and those who don't.

Note: (as of now) only.. 1 and 4 applies (i am on my way...)
Post #1431424
Danny Ocean
Posted Friday, March 15, 2013 4:08 AM


Ten Centuries

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kapil_kk (3/15/2013)
Danny Ocean (3/15/2013)
Really a nice and good question.

one more thing apart from this question. if you set ARITHABORT OFF and then execute below code, it will give output as "*" due to insufficient char length. and if you set char length more than 7, it will give "0.111111".

It denotes that we need to provide an insufficient length whenever we convert values in char or varchar.

[code="sql"]
SET ARITHABORT OFF
select isnull ( convert (char(3),1.0/9) ,'*')


Vinay, I tried with ARITHABORT OFF but still I am getting same error "Arithmetic overflow error converting numeric to data type varchar."
set arithabort off
select ISNULL(CONVERT(char(3),1.0/9),'*')


Kapil, you need to SET ANSI_WARNINGS OFF. Look at below two examples. Example 1 execute successfully but example 2 give an error.



---- Example 1
SET ANSI_WARNINGS OFF
SET ARITHABORT OFF
GO

select isnull ( convert (char(3),1.0/9) ,'*') ,isnull ( convert (char(8),1.0/9) ,'*')
GO

SET ARITHABORT ON
SET ANSI_WARNINGS ON



---- Example 2
SET ANSI_WARNINGS ON
GO

select isnull ( convert (char(3),1.0/9) ,'*') ,isnull ( convert (char(8),1.0/9) ,'*')
GO

Keep Learning - Keep Growing !!!
http://growwithsql.blogspot.in

Thanks
Vinay Kumar
Post #1431434
Stewart "Arturius" Campbell
Posted Friday, March 15, 2013 4:40 AM


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Nice, simple question to end the week, thanks Eli

____________________________________________
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All limits henceforth are self-imposed.
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Post #1431442
Dave Morris
Posted Friday, March 15, 2013 4:44 AM
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Nice question, thanks. It made me think - I better rest now ......
Post #1431446
kapil_kk
Posted Friday, March 15, 2013 5:25 AM


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Danny Ocean (3/15/2013)
kapil_kk (3/15/2013)
Danny Ocean (3/15/2013)
Really a nice and good question.

one more thing apart from this question. if you set ARITHABORT OFF and then execute below code, it will give output as "*" due to insufficient char length. and if you set char length more than 7, it will give "0.111111".

It denotes that we need to provide an insufficient length whenever we convert values in char or varchar.

[code="sql"]
SET ARITHABORT OFF
select isnull ( convert (char(3),1.0/9) ,'*')


Vinay, I tried with ARITHABORT OFF but still I am getting same error "Arithmetic overflow error converting numeric to data type varchar."
set arithabort off
select ISNULL(CONVERT(char(3),1.0/9),'*')


Kapil, you need to SET ANSI_WARNINGS OFF. Look at below two examples. Example 1 execute successfully but example 2 give an error.



---- Example 1
SET ANSI_WARNINGS OFF
SET ARITHABORT OFF
GO

select isnull ( convert (char(3),1.0/9) ,'*') ,isnull ( convert (char(8),1.0/9) ,'*')
GO

SET ARITHABORT ON
SET ANSI_WARNINGS ON



---- Example 2
SET ANSI_WARNINGS ON
GO

select isnull ( convert (char(3),1.0/9) ,'*') ,isnull ( convert (char(8),1.0/9) ,'*')
GO



Yes, It works....
Post #1431465
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