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 Posted Wednesday, December 05, 2012 12:41 PM
 Forum Newbie Group: General Forum Members Last Login: Thursday, December 13, 2012 6:34 PM Points: 6, Visits: 58
 Problem: Bank requires to find out number of months customs have spent money more then certain amount in consecutive monthor sales department requires to find out number of months a product has been sold more then certain amount in consecutive month.If data is just in few months or just require for 2 or 3 consecutive months, then simple table join can do it.But we have like years records, and need count all consecutive months, it will could be hard to hard coding all table join for 2, 3, 4 ,5 ... consecutive months.There is an easy way using recursive CTE to solve such a problem.For example, a table store sales records like below. And we need to list number of consecutive months for any sale who sold a product more then 2 in a month. It is can be done easily by following recursive CTE querysample dataCREATE TABLE #sales( [name] [varchar](50) NOT NULL, [saledate] [datetime] NULL, [quantity] [int] NULL) insert into #sales(name,saledate,quantity)values ('A','2012-01-01',1), ('A','2012-02-01',2), ('A','2012-03-01',3), ('A','2012-04-01',4), ('A','2012-05-01',5), ('A','2012-06-01',6) insert into #sales(name,saledate,quantity)values ('B','2012-01-01',6), ('B','2012-02-01',2), ('B','2012-03-01',3), ('B','2012-04-01',4), ('B','2012-05-01',1), ('B','2012-06-01',6) insert into #sales(name,saledate,quantity)values ('C','2012-01-01',6), ('C','2012-02-01',1), ('C','2012-03-01',3), ('C','2012-04-01',1), ('C','2012-05-01',4), ('C','2012-06-01',1) insert into #sales(name,saledate,quantity)values ('D','2012-01-01',6), ('D','2012-02-01',3), ('D','2012-03-01',3), ('D','2012-04-01',4), ('D','2012-05-01',1), ('D','2012-06-01',6)-- wm for all months in which product sold more 2with wm as ( select name,saledate from #sales where quantity>2 ),-- only using above qualified records, not all records to do recursive join base_cte (name,saledate ) as ( select * from wm union all select a.name,a.saledate from wm a inner join base_cte b on a.name=b.name and a.saledate=dateadd(month,1,b.saledate) )-- the count column indicates number of consecutive month for that month. select b.name,b.saledate, COUNT(b.name) as cnt from base_cte b group by b.name,b.saledate order by b.name,b.saledate-- for example cnt = 2, meaning that month is the second month, from which, backward in 2 -- consecutive month, a product was sold more then 2 each month -- cnt = 3, meaning that month is the third month, from which, backward in 3 -- consecutive month, a product was sold more then 2
Post #1393173
 Posted Wednesday, December 05, 2012 3:04 PM
 SSC Eights! Group: General Forum Members Last Login: Monday, October 21, 2013 12:44 PM Points: 945, Visits: 1,753
 This looks like a gaps and island problem. it also from the problem description sounds like homework or an interview question.Take a look at this for a detailed explanation and solution of the problem. http://www.manning.com/nielsen/nielsenMEAP_freeCh5.pdf Specifically part two chapter 5 For faster help in answering any problems Please read How to post data/code on a forum to get the best help - Jeff Moden for the best way to ask your question.For performance Issues see how we like them posted here: How to Post Performance Problems - Gail ShawNeed to Split some strings? Jeff Moden's DelimitedSplit8KJeff Moden's Cross tab and Pivots Part 1Jeff Moden's Cross tab and Pivots Part 2Jeremy Oursler
Post #1393236
 Posted Wednesday, December 05, 2012 3:08 PM
 SSChasing Mays Group: General Forum Members Last Login: Yesterday @ 11:14 PM Points: 604, Visits: 1,994
 Using Jeff Moden's article http://www.sqlservercentral.com/articles/T-SQL/71550/ about Group Islands of Contiguous Dates as inspiration, you could do the following`;WITH cte AS ( SELECT name, DATEADD(mm, - ROW_NUMBER() OVER (ORDER BY name, saledate), saledate) dategroup, saledate FROM #sales WHERE quantity > 2 )SELECT name, MIN(saledate) firstsaledate, COUNT(*) cntFROM cteGROUP BY name, dategroupORDER BY name, dategroup`
Post #1393237
 Posted Wednesday, December 05, 2012 3:37 PM
 SSCommitted Group: General Forum Members Last Login: Tuesday, January 15, 2013 11:11 AM Points: 1,945, Visits: 2,782
 Sales department requires to find out number of months a product has been sold more then certain amount in consecutive month.If data is just in few months or just require for 2 or 3 consecutive months, then simple table join can do it.But we have like years rows, and need count all consecutive months, it will could be hard to hard coding all table join for 2, 3, 4 , 5 ... consecutive months.There is an easy way using recursive CTE to solve such a problem.For example, a table store Sales rows like below. And we need to list number of consecutive months for any salesman who sold a product more then 2 in a month. It is can be done easily by following recursive CTE queryCREATE TABLE Sales(salesman_name CHAR(10) NOT NULL, sale_date CHAR(10) NOT NULL, PRIMARY KEY (salesman_name, sale_date), sale_qty INTEGER NOT NULL CHECK (sale_qty > 0));INSERT INTO SalesVALUES('A', '2012-01-00', 1), ('A', '2012-02-00', 2), ('A', '2012-03-00', 3), ('A', '2012-04-00', 4), ('A', '2012-05-00', 5), ('A', '2012-06-00', 6),('B', '2012-01-00', 6), ('B', '2012-02-00', 2), ('B', '2012-03-00', 3), ('B', '2012-04-00', 4), ('B', '2012-05-00', 1), ('B', '2012-06-00', 6), ('C', '2012-01-00', 6), ('C', '2012-02-00', 1), ('C', '2012-03-00', 3), ('C', '2012-04-00', 1), ('C', '2012-05-00', 4), ('C', '2012-06-00', 1), ('D', '2012-01-00', 6), ('D', '2012-02-00', 3), ('D', '2012-03-00', 3), ('D', '2012-04-00', 4), ('D', '2012-05-00', 1), ('D', '2012-06-00', 6);WITH X1 AS (SELECT salesman_name, sale_date, sale_qty, ROW_NUMBER() OVER (PARTITION BY salesman_name ORDER BY salesman_name, sale_date) AS r1 FROM Sales), X2 AS (SELECT salesman_name, sale_date, sale_qty, r1- ROW_NUMBER() OVER (PARTITION BY salesman_name ORDER BY salesman_name, sale_date) AS sale_grp FROM X1 WHERE sale_qty > 2) SELECT salesman_name, MIN(sale_date), MAX(sale_date) FROM X2 GROUP BY salesman_name, sale_grp; Books in Celko Series for Morgan-Kaufmann PublishingAnalytics and OLAP in SQL Data and Databases: Concepts in Practice Data, Measurements and Standards in SQLSQL for SmartiesSQL Programming Style SQL Puzzles and Answers Thinking in SetsTrees and Hierarchies in SQL
Post #1393250
 Posted Wednesday, December 05, 2012 4:04 PM
 Forum Newbie Group: General Forum Members Last Login: Thursday, December 13, 2012 6:34 PM Points: 6, Visits: 58
 I know Jeff Moden's solution.But I assume this way could be faster because there is not sorting for row number. At least, it is a different solution.
Post #1393260
 Posted Wednesday, December 05, 2012 4:39 PM
 SSC-Dedicated Group: General Forum Members Last Login: Today @ 2:35 AM Points: 34,550, Visits: 28,728
 bj_shenglong (12/5/2012)But I assume this way could be faster...That's how rumors of performance get started. Write code to build a million row test table and test your hypothesis. No matter which way it turns out, we'll all learn something if you post the results. See the following articles for how to do such a thing pretty easily and quickly.http://www.sqlservercentral.com/articles/Data+Generation/87901/http://www.sqlservercentral.com/articles/Test+Data/88964/ --Jeff Moden"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column." "Change is inevitable. Change for the better is not." -- 04 August 2013(play on words) "Just because you CAN do something in T-SQL, doesn't mean you SHOULDN'T." --22 Aug 2013Helpful Links:How to post code problemsHow to post performance problems
Post #1393267
 Posted Wednesday, December 05, 2012 5:41 PM
 Forum Newbie Group: General Forum Members Last Login: Thursday, December 13, 2012 6:34 PM Points: 6, Visits: 58
 There is a particular problem, let's' say, we just want to find out who sold more then 2 each month in at least two consecutive months and when.For the above sample, below recursion would work. Also, recursion will stop immediately when it reaches the first qualified date. with m2_cte_f (name,saledate,quantity,ind) as ( select s.*, 0 as ind from #sales s where s.saledate='2012-01-01' union all select s.*, case when s.quantity > 2 and sc.quantity > 2 then 1 else 0 end as ind from #sales s inner join m2_cte_f sc on (s.saledate = dateadd(month,1,sc.saledate) and s.name=sc.name) where sc.ind = 0 ) select * from m2_cte_f where ind=1
Post #1393282
 Posted Wednesday, December 05, 2012 8:13 PM
 SSChasing Mays Group: General Forum Members Last Login: Yesterday @ 11:14 PM Points: 604, Visits: 1,994
 So comparing the islands and recursive queries returning similar rows`;WITH cte AS ( SELECT name, DATEADD(mm, - ROW_NUMBER() OVER (ORDER BY name, saledate), saledate) dategroup, saledate FROM #sales WHERE quantity > 2 and saledate >= '2012-01-01' )SELECT name, max(saledate), COUNT(*)FROM cteGROUP BY name, dategroupHAVING COUNT(*) > 1 ORDER BY name, dategroup;with m2_cte_f (name,saledate,quantity,ind) as (select s.*, 0 as indfrom #sales swhere s.saledate='2012-01-01'union allselect s.*, case when s.quantity > 2 and sc.quantity > 2 then 1 else 0 end as indfrom #sales sinner join m2_cte_f sc on (s.saledate = dateadd(month,1,sc.saledate) and s.name=sc.name)where sc.ind = 0 )select * from m2_cte_f where ind=1 `I get the following IO stats (timing not worth mentioning 1ms each) for the small test set`(3 row(s) affected)Table '#sales____00000000009F'. Scan count 1, logical reads 1, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.(3 row(s) affected)Table 'Worktable'. Scan count 2, logical reads 91, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.Table '#sales____00000000009F'. Scan count 2, logical reads 14, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.`Upping the stakes a tiny bit by putting a moderate amount of data (3000 odd rows) into the table`INSERT INTO #sales (name, saledate)SELECT *FROM (SELECT * FROM (VALUES('A'),('B'),('C'),('D'),('E'),('F'),('G'),('H'),('I'),('J'),('K'),('L'),('M'),('N'),('O'),('P'),('Q'),('R'),('S'),('T')) as sales(name)) names, (SELECT TOP 156 dateadd(mm, N, '1999-12-01') saledate FROM Tally) as months UPDATE #salesSET quantity = RAND(Checksum(Newid())) * 5CREATE CLUSTERED INDEX SALES_IDX1 ON #sales (saledate, name)`I get the following`(22 row(s) affected)Table '#sales__0000000000A4'. Scan count 1, logical reads 4, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. SQL Server Execution Times: CPU time = 0 ms, elapsed time = 1 ms.(15 row(s) affected)Table 'Worktable'. Scan count 2, logical reads 635, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.Table '#sales__0000000000A4'. Scan count 96, logical reads 193, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. SQL Server Execution Times: CPU time = 0 ms, elapsed time = 3 ms.`As I added more rows to the table the recursive query got very gradually slower and did more reads, while the islands query remained static. I got up to 75816 rows. Would you believe the had sales data back to 1770 for the same 26 people `(27 row(s) affected)Table '#sales__0000000000AD'. Scan count 1, logical reads 4, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. SQL Server Execution Times: CPU time = 0 ms, elapsed time = 1 ms.(19 row(s) affected)Table 'Worktable'. Scan count 2, logical reads 1193, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.Table '#sales__0000000000AD'. Scan count 189, logical reads 380, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. SQL Server Execution Times: CPU time = 0 ms, elapsed time = 5 ms.`
Post #1393299
 Posted Wednesday, December 05, 2012 9:22 PM
 SSC-Dedicated Group: General Forum Members Last Login: Today @ 2:35 AM Points: 34,550, Visits: 28,728
 bj_shenglong (12/5/2012)There is a particular problem, let's' say, we just want to find out who sold more then 2 each month in at least two consecutive months and when.For the above sample, below recursion would work. Also, recursion will stop immediately when it reaches the first qualified date.Although they can be fast, recursive CTEs are still procedural in nature. The only way to know for sure is to do a test.{Edit} Was distracted by a code promotion going on at work and I see that MickyT made just such a test. Thank you, good Sir! --Jeff Moden"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column." "Change is inevitable. Change for the better is not." -- 04 August 2013(play on words) "Just because you CAN do something in T-SQL, doesn't mean you SHOULDN'T." --22 Aug 2013Helpful Links:How to post code problemsHow to post performance problems
Post #1393312
 Posted Wednesday, December 05, 2012 10:32 PM
 SSC-Enthusiastic Group: General Forum Members Last Login: Today @ 2:49 AM Points: 148, Visits: 296
 this is my contribution`USE tempdbGOIF OBJECT_ID('TestTbl') IS NOT NULL DROP TABLE TestTblCREATE TABLE Testtbl (id INT PRIMARY KEY) INSERT INTO Testtbl( id)SELECT TOP 1000 ROW_NUMBER() OVER ( ORDER BY c.object_id) id FROM sys.[columns] c ,sys.[columns] c2DELETE FROM TestTbl WHERE id IN(SELECT top 100 ABS(CHECKSUM(NEWID())%1000) FROM sys.[columns] c)DELETE FROM TestTbl WHERE id IN(SELECT top 100 ABS(CHECKSUM(NEWID())%1000) FROM sys.[columns] c)SELECT * FROM TestTbl;WITH S AS (SELECT ROW_NUMBER() OVER (order by t.id) AS RN,t.id FROM TestTbl t LEFT OUTER JOIN TestTbl t2 ON t.id -1= t2.id WHERE t2.id IS NULL ),E AS (SELECT ROW_NUMBER() OVER (order by t.id) AS RN, t.id FROM TestTbl t LEFT OUTER JOIN TestTbl t2 ON t.id +1= t2.idWHERE t2.id IS NULL )SELECT s.id AS [START], e.id AS [END] FROM S INNER JOIN E ON s.Rn= E.rn GO`using this i try to solve your problem`USE tempdbGOIF OBJECT_ID('sales') IS NOT NULL DROP TABLE salesCREATE TABLE sales([name] [varchar](50) NOT NULL,[saledate] [datetime] NULL,[quantity] [int] NULL)GOInsert into sales(name,saledate,quantity)values('A','2012-01-01',1),('A','2012-02-01',2),('A','2012-03-01',3),('A','2012-04-01',4),('A','2012-05-01',5),('A','2012-06-01',6),('B','2012-01-01',6),('B','2012-02-01',2),('B','2012-03-01',3),('B','2012-04-01',4),('B','2012-05-01',1),('B','2012-06-01',6),('C','2012-01-01',6),('C','2012-02-01',1),('C','2012-03-01',3),('C','2012-04-01',1),('C','2012-05-01',4),('C','2012-06-01',1),('D','2012-01-01',6),('D','2012-02-01',3),('D','2012-03-01',3),('D','2012-04-01',4),('D','2012-05-01',1),('D','2012-06-01',6);WITH Fil AS ( SELECT * FROM sales WHERE quantity > 2 ), S AS ( SELECT ROW_NUMBER() OVER (ORDER BY t.name) AS RN, t.NAME, MONTH (t.saledate) AS id FROM Fil t LEFT OUTER JOIN Fil t2 ON MONTH (t.saledate) -1 = MONTH (t2.saledate) AND t2.name = t.name WHERE t2.saledate IS NULL ),E AS ( SELECT ROW_NUMBER() OVER (ORDER BY t.name) AS RN, t.NAME, MONTH (t.saledate) AS id FROM Fil t LEFT OUTER JOIN Fil t2 ON MONTH (t.saledate) + 1 = MONTH (t2.saledate) AND t2.name = t.name WHERE t2.saledate IS NULL ),Gap AS( SELECT e.NAME, s.id AS [DateStart], e.id AS [DateEnd] FROM S INNER JOIN E ON s.Rn = E.rn --AND s.id<>e.id )SELECT g.NAME ,g.Datestart, sum(CASE WHEN(sales.quantity>2) AND MONTH(sales.saledate) BETWEEN g.datestart AND g.dateend THEN 1 ELSE 0 END ) as ResFROM sales INNER JOIN gap g ON sales.name =g.NAME AND month(sales.saledate)>= g.datestart GROUP BY g.name,g.DatestartORDER BY g.name,g.Datestart`i miss the criteria
Post #1393321

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