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 find increase/decrease amount Rate Topic Display Mode Topic Options
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 Posted Monday, October 1, 2012 1:34 AM
 SSC Rookie Group: General Forum Members Last Login: Monday, July 18, 2016 6:37 PM Points: 38, Visits: 525
 i want to find the increase / decrease amount group by sector and month.--input table declare @t table ([id] int,[Amount] int,monthno int,Sector char(1));INSERT INTO @t ([id],[Amount],Monthno ,sector )VALUES (1, 100,1,'A'), (2,50,1,'A'), (3, 200,1,'B'), (4, 300,1,'C'), (5, 400,2,'A'), (6, 500,2,'B'), (7, 600,2,'C'), (8, 100,3,'A'), (9, 500,3,'B'), (10, 100,3,'C')select * from @t -- Required Outputdeclare @output table ([IncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))INSERT INTO @output ([IncreaseDecreaseAmount],Amount,[Monthno],sector )VALUES (50,100,1,'A'), (300,400,2,'A'), (-200,100,3,'A'), (200,200,1,'B'), (300,500,2,'B'), (0,500,3,'B')select * from @output regards,
Post #1366344
 Posted Monday, October 1, 2012 2:52 AM
 SSC-Addicted Group: General Forum Members Last Login: Thursday, September 29, 2016 5:30 AM Points: 424, Visits: 1,271
 What are the rules for calculating increase & decrease?It's not obvious from the expected results.
Post #1366399
 Posted Monday, October 1, 2012 5:27 AM
 SSC Rookie Group: General Forum Members Last Login: Monday, July 18, 2016 6:37 PM Points: 38, Visits: 525
 the rule here is we have month no here.1. check secondmonth amount2. sum(second month amount) > sum(first month amount)3. get the difference 4. difference is greater then sum(first month amount) then it shows addition.5. difference is less then sum(first month amount) then it shows reduction 6. check the amount for month3 7. sum of (First Month+second month) > sum of (third month) 8. difference is greater then sum(first+second month amount) then it shows addition.9. difference is less then sum(first+second month amount) then it shows reduction it shall be grouped by monthno and sector.
Post #1366494
 Posted Tuesday, October 2, 2012 2:54 AM
 SSC-Addicted Group: General Forum Members Last Login: Thursday, September 29, 2016 5:30 AM Points: 424, Visits: 1,271
 sayedkhalid99 (10/1/2012)the rule here is we have month no here.1. check secondmonth amount2. sum(second month amount) > sum(first month amount)3. get the difference 4. difference is greater then sum(first month amount) then it shows addition.5. difference is less then sum(first month amount) then it shows reduction 6. check the amount for month3 7. sum of (First Month+second month) > sum of (third month) 8. difference is greater then sum(first+second month amount) then it shows addition.9. difference is less then sum(first+second month amount) then it shows reduction it shall be grouped by monthno and sector.I still can't follow that.Can you give the values for Sector A with the steps above? That should make it clearer.
Post #1366908
 Posted Tuesday, October 2, 2012 4:51 AM
 SSCrazy Eights Group: General Forum Members Last Login: Thursday, December 1, 2016 10:11 AM Points: 8,587, Visits: 18,753
 ` -- you have 2 rows for sector 'A', month 1 -- what do you want to do with them? -- It's not clear from your "Required Output", which is incorrect -- see row 3. SELECT [IncreaseDecreaseAmount] = ISNULL(cr.Amount-lr.Amount,cr.Amount), cr.Amount, cr.Monthno, cr.sectorFROM @t crLEFT JOIN ( SELECT Sector, monthno, [Amount] = SUM([Amount]) FROM @t GROUP BY Sector, monthno) lr ON lr.Sector = cr.Sector AND lr.monthno+1 = cr.monthno ORDER BY cr.sector, cr.Monthno` “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps
Post #1366952
 Posted Tuesday, October 2, 2012 10:53 PM
 SSC Rookie Group: General Forum Members Last Login: Monday, July 18, 2016 6:37 PM Points: 38, Visits: 525
 i have changed the my input and output and add date and comments to make it clear, for multiple entry with in a month it shall take the last entry.declare @t table([id] int,[Amount] int,Sector char(1),Currentdate datetime);INSERT INTO @t([id],[Amount],Sector,currentdate )VALUES(1, 100,'A','2002-01-01 00:00:00.000'),(2,50,'A','2002-01-02 00:00:00.000'),(3, 200,'B','2002-01-01 00:00:00.000'),(4, 300,'C','2002-01-01 00:00:00.000'),(5, 400,'A','2002-02-02 00:00:00.000'),(6, 500,'B','2002-02-02 00:00:00.000'),(7, 600,'C','2002-02-02 00:00:00.000'),(8, 100,'A','2002-03-02 00:00:00.000'),(9, 500,'B','2002-03-03 00:00:00.000'),(10, 100,'C','2002-03-03 00:00:00.000'),(11, 200,'C','2002-03-03 00:00:00.000')select * from @tdeclare @output table ([AfterIncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))INSERT INTO @output([AfterIncreaseDecreaseAmount],Amount,[Monthno],sector )VALUES(50,100,1,'A'), -- for 01/01/2002 it is 100 , for 02/02/2002 for multiple entry with in the month it shall take the last amount based on max(id) or last(currentdate).(+350,400,2,'A'), -- for second month 02/02/2002 it 400 > 50 it shows increase from first month so 400-50=+350 so --> AfterIncreaseDecreaseAmount=350(-300,100,3,'A'), -- for third month 02/03/2002 it is 100 < 400 (sum of 1st,2st month amount) so it shows decrease 100-400=-300 so-->AfterIncreaseDecreaseAmount=-300 (+200,200,1,'B'),-- for b we have 200 it is 200 > 0 ,if it is only one it shall count that as 0 so it shows increase 200-0=200 --> AfterIncreaseDecrease=200 (+300,500,2,'B'),-- for b we have 500 500 > 200--> 500-200=300 it show increased -->AfterIncreaseDecrease=300(0,500,3,'B'), -- for b in third month 500-500(sum of 1st,2stmonth amount of b) =0 AfterIncreaseDecrease=0(+300,300,1,'C'),(+300,600,2,'C'),(400,100,3,'C')select * from @output
Post #1367400
 Posted Wednesday, October 3, 2012 7:39 AM
 SSCrazy Eights Group: General Forum Members Last Login: Thursday, December 1, 2016 10:11 AM Points: 8,587, Visits: 18,753