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 Posted Monday, October 01, 2012 1:34 AM
 SSC Rookie Group: General Forum Members Last Login: Tuesday, April 08, 2014 12:23 PM Points: 31, Visits: 370
 i want to find the increase / decrease amount group by sector and month.--input table declare @t table ([id] int,[Amount] int,monthno int,Sector char(1));INSERT INTO @t ([id],[Amount],Monthno ,sector )VALUES (1, 100,1,'A'), (2,50,1,'A'), (3, 200,1,'B'), (4, 300,1,'C'), (5, 400,2,'A'), (6, 500,2,'B'), (7, 600,2,'C'), (8, 100,3,'A'), (9, 500,3,'B'), (10, 100,3,'C')select * from @t -- Required Outputdeclare @output table ([IncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))INSERT INTO @output ([IncreaseDecreaseAmount],Amount,[Monthno],sector )VALUES (50,100,1,'A'), (300,400,2,'A'), (-200,100,3,'A'), (200,200,1,'B'), (300,500,2,'B'), (0,500,3,'B')select * from @output regards,
Post #1366344
 Posted Monday, October 01, 2012 2:52 AM
 Old Hand Group: General Forum Members Last Login: Wednesday, March 19, 2014 9:43 AM Points: 316, Visits: 1,022
 What are the rules for calculating increase & decrease?It's not obvious from the expected results.
Post #1366399
 Posted Monday, October 01, 2012 5:27 AM
 SSC Rookie Group: General Forum Members Last Login: Tuesday, April 08, 2014 12:23 PM Points: 31, Visits: 370
 the rule here is we have month no here.1. check secondmonth amount2. sum(second month amount) > sum(first month amount)3. get the difference 4. difference is greater then sum(first month amount) then it shows addition.5. difference is less then sum(first month amount) then it shows reduction 6. check the amount for month3 7. sum of (First Month+second month) > sum of (third month) 8. difference is greater then sum(first+second month amount) then it shows addition.9. difference is less then sum(first+second month amount) then it shows reduction it shall be grouped by monthno and sector.
Post #1366494
 Posted Monday, October 01, 2012 5:24 PM
 SSCommitted Group: General Forum Members Last Login: Tuesday, January 15, 2013 11:11 AM Points: 1,945, Visits: 2,782
 I want to find the increase / decrease amount group by sector and month. It is a lot easier if you post DDL for a base table, so we can see keys and constraints. We now have to guess at everything and correct your DDL to conform to ISO-11179 rules; your data element names are so generic as to be useless. This is called a delta, from the Greek letter that mathematicians use for changes Months are temporal values, not integers. I like to use the MySQL convention for months; you can Google it. CREATE TABLE Foobars(foo_id INTEGER NOT NULL, sector_code CHAR(1), PRIMARY KEY (foo_id, sector_code), foobar_qty INTEGER NOT NULL CHECK (foobar_qty > 0), report_month CHAR(10) NOT NULL CHECK (report_month LIKE '[12][0-9][0-9][0-9]-[0-3][0-9]-00')); INSERT INTO Foobars(foo_id, foobar_qty, report_month , sector_code)VALUES(2, 'A', 50, '2012-01-00'), (3, 'B', 200, '2012-01-00'), (4, 'C', 300, '2012-01-00'), (5, 'A', 400, '2012-02-00'), (6, 'B', 500, '2012-02-00'), (7, 'C', 600, '2012-02-00'), (8, 'A', 100, '2012-03-00'), (9, 'B', 500, '2012-03-00'), (10, 'C', 100, '2012-03-00');Your specs and your sample output do not match. The first row has two sectors in one monthWITH Month_Totals (report_month, sector_code, month_qty_tot)AS(SELECT report_month, sector_code, SUM (foobar_qty) FROM Foobars GROUP BY report_month, sector_code)SELECT report_month, sector_code, month_qty_tot, ( month_qty_tot - LAG(month_qty_tot) OVER (PARTITION BY sector_code ORDER BY report_month ASC)) AS delta FROM Month_Totals ORDER BY sector_code, report_month FROM Month_Totals; Books in Celko Series for Morgan-Kaufmann PublishingAnalytics and OLAP in SQL Data and Databases: Concepts in Practice Data, Measurements and Standards in SQLSQL for SmartiesSQL Programming Style SQL Puzzles and Answers Thinking in SetsTrees and Hierarchies in SQL
Post #1366832
 Posted Tuesday, October 02, 2012 2:54 AM
 Old Hand Group: General Forum Members Last Login: Wednesday, March 19, 2014 9:43 AM Points: 316, Visits: 1,022
 sayedkhalid99 (10/1/2012)the rule here is we have month no here.1. check secondmonth amount2. sum(second month amount) > sum(first month amount)3. get the difference 4. difference is greater then sum(first month amount) then it shows addition.5. difference is less then sum(first month amount) then it shows reduction 6. check the amount for month3 7. sum of (First Month+second month) > sum of (third month) 8. difference is greater then sum(first+second month amount) then it shows addition.9. difference is less then sum(first+second month amount) then it shows reduction it shall be grouped by monthno and sector.I still can't follow that.Can you give the values for Sector A with the steps above? That should make it clearer.
Post #1366908
 Posted Tuesday, October 02, 2012 4:51 AM
 SSCertifiable Group: General Forum Members Last Login: Today @ 5:08 AM Points: 6,772, Visits: 12,875
 ` -- you have 2 rows for sector 'A', month 1 -- what do you want to do with them? -- It's not clear from your "Required Output", which is incorrect -- see row 3. SELECT [IncreaseDecreaseAmount] = ISNULL(cr.Amount-lr.Amount,cr.Amount), cr.Amount, cr.Monthno, cr.sectorFROM @t crLEFT JOIN ( SELECT Sector, monthno, [Amount] = SUM([Amount]) FROM @t GROUP BY Sector, monthno) lr ON lr.Sector = cr.Sector AND lr.monthno+1 = cr.monthno ORDER BY cr.sector, cr.Monthno` “Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail ShawFor fast, accurate and documented assistance in answering your questions, please read this article.Understanding and using APPLY, (I) and (II) Paul White Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff ModenExploring Recursive CTEs by Example Dwain Camps
Post #1366952
 Posted Tuesday, October 02, 2012 10:53 PM
 SSC Rookie Group: General Forum Members Last Login: Tuesday, April 08, 2014 12:23 PM Points: 31, Visits: 370
 i have changed the my input and output and add date and comments to make it clear, for multiple entry with in a month it shall take the last entry.declare @t table([id] int,[Amount] int,Sector char(1),Currentdate datetime);INSERT INTO @t([id],[Amount],Sector,currentdate )VALUES(1, 100,'A','2002-01-01 00:00:00.000'),(2,50,'A','2002-01-02 00:00:00.000'),(3, 200,'B','2002-01-01 00:00:00.000'),(4, 300,'C','2002-01-01 00:00:00.000'),(5, 400,'A','2002-02-02 00:00:00.000'),(6, 500,'B','2002-02-02 00:00:00.000'),(7, 600,'C','2002-02-02 00:00:00.000'),(8, 100,'A','2002-03-02 00:00:00.000'),(9, 500,'B','2002-03-03 00:00:00.000'),(10, 100,'C','2002-03-03 00:00:00.000'),(11, 200,'C','2002-03-03 00:00:00.000')select * from @tdeclare @output table ([AfterIncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))INSERT INTO @output([AfterIncreaseDecreaseAmount],Amount,[Monthno],sector )VALUES(50,100,1,'A'), -- for 01/01/2002 it is 100 , for 02/02/2002 for multiple entry with in the month it shall take the last amount based on max(id) or last(currentdate).(+350,400,2,'A'), -- for second month 02/02/2002 it 400 > 50 it shows increase from first month so 400-50=+350 so --> AfterIncreaseDecreaseAmount=350(-300,100,3,'A'), -- for third month 02/03/2002 it is 100 < 400 (sum of 1st,2st month amount) so it shows decrease 100-400=-300 so-->AfterIncreaseDecreaseAmount=-300 (+200,200,1,'B'),-- for b we have 200 it is 200 > 0 ,if it is only one it shall count that as 0 so it shows increase 200-0=200 --> AfterIncreaseDecrease=200 (+300,500,2,'B'),-- for b we have 500 500 > 200--> 500-200=300 it show increased -->AfterIncreaseDecrease=300(0,500,3,'B'), -- for b in third month 500-500(sum of 1st,2stmonth amount of b) =0 AfterIncreaseDecrease=0(+300,300,1,'C'),(+300,600,2,'C'),(400,100,3,'C')select * from @output
Post #1367400
 Posted Wednesday, October 03, 2012 7:39 AM
 SSCertifiable Group: General Forum Members Last Login: Today @ 5:08 AM Points: 6,772, Visits: 12,875