find increase/decrease amount

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find increase/decrease amount

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sayedkhalid99

Posted Monday, October 01, 2012 1:34 AM

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i want to find the increase / decrease amount group by sector and month.
--input table
declare @t table
([id] int,[Amount] int,monthno int,Sector char(1));
INSERT INTO @t
([id],[Amount],Monthno ,sector )
VALUES
(1, 100,1,'A'),
(2,50,1,'A'),
(3, 200,1,'B'),
(4, 300,1,'C'),
(5, 400,2,'A'),
(6, 500,2,'B'),
(7, 600,2,'C'),
(8, 100,3,'A'),
(9, 500,3,'B'),
(10, 100,3,'C')
select * from @t

-- Required Output

declare @output table ([IncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))
INSERT INTO @output
([IncreaseDecreaseAmount],Amount,[Monthno],sector )
VALUES
(50,100,1,'A'),
(300,400,2,'A'),
(-200,100,3,'A'),
(200,200,1,'B'),
(300,500,2,'B'),
(0,500,3,'B')
select * from @output

regards,

Post #1366344

laurie-789651

Posted Monday, October 01, 2012 2:52 AM

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What are the rules for calculating increase & decrease?

It's not obvious from the expected results.

Post #1366399

sayedkhalid99

Posted Monday, October 01, 2012 5:27 AM

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the rule here is we have month no here.

1. check secondmonth amount

2. sum(second month amount) > sum(first month amount)

3. get the difference

4. difference is greater then sum(first month amount) then it shows addition.

5. difference is less then sum(first month amount) then it shows reduction

6. check the amount for month3

7. sum of (First Month+second month) > sum of (third month)

8. difference is greater then sum(first+second month amount) then it shows addition.

9. difference is less then sum(first+second month amount) then it shows reduction

it shall be grouped by monthno and sector.

Post #1366494

CELKO

Posted Monday, October 01, 2012 5:24 PM

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I want to find the increase / decrease amount group by sector and month.

It is a lot easier if you post DDL for a base table, so we can see keys and constraints. We now have to guess at everything and correct your DDL to conform to ISO-11179 rules; your data element names are so generic as to be useless. This is called a delta, from the Greek letter that mathematicians use for changes

Months are temporal values, not integers. I like to use the MySQL convention for months; you can Google it.

CREATE TABLE Foobars
(foo_id INTEGER NOT NULL,
sector_code CHAR(1),
PRIMARY KEY (foo_id, sector_code),
foobar_qty INTEGER NOT NULL
CHECK (foobar_qty > 0),
report_month CHAR(10) NOT NULL
CHECK (report_month LIKE '[12][0-9][0-9][0-9]-[0-3][0-9]-00'));

INSERT INTO Foobars
(foo_id, foobar_qty, report_month , sector_code)
VALUES

(2, 'A', 50, '2012-01-00'),
(3, 'B', 200, '2012-01-00'),
(4, 'C', 300, '2012-01-00'),
(5, 'A', 400, '2012-02-00'),
(6, 'B', 500, '2012-02-00'),
(7, 'C', 600, '2012-02-00'),
(8, 'A', 100, '2012-03-00'),
(9, 'B', 500, '2012-03-00'),
(10, 'C', 100, '2012-03-00');

Your specs and your sample output do not match. The first row has two sectors in one month

WITH Month_Totals (report_month, sector_code, month_qty_tot)
AS
(SELECT report_month, sector_code, SUM (foobar_qty)
FROM Foobars
GROUP BY report_month, sector_code)

SELECT report_month, sector_code, month_qty_tot,
( month_qty_tot - LAG(month_qty_tot)
OVER (PARTITION BY sector_code
ORDER BY report_month ASC)) AS delta
FROM Month_Totals
ORDER BY sector_code, report_month
FROM Month_Totals;

Books in Celko Series for Morgan-Kaufmann Publishing
Analytics and OLAP in SQL
Data and Databases: Concepts in Practice
Data, Measurements and Standards in SQL
SQL for Smarties
SQL Programming Style
SQL Puzzles and Answers
Thinking in Sets
Trees and Hierarchies in SQL

Post #1366832

laurie-789651

Posted Tuesday, October 02, 2012 2:54 AM

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sayedkhalid99 (10/1/2012)

I still can't follow that.

Can you give the values for Sector A with the steps above? That should make it clearer.

Post #1366908

ChrisM@Work

Posted Tuesday, October 02, 2012 4:51 AM

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Last Login: Today @ 9:27 AM
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 -- you have 2 rows for sector 'A', month 1
 -- what do you want to do with them? 
 -- It's not clear from your "Required Output", which is incorrect
 -- see row 3. 
SELECT 
	[IncreaseDecreaseAmount] = ISNULL(cr.Amount-lr.Amount,cr.Amount), 
	cr.Amount, 
	cr.Monthno, 
	cr.sector
FROM @t cr
LEFT JOIN (
	SELECT Sector, monthno, [Amount] = SUM([Amount]) 
	FROM @t 
	GROUP BY Sector, monthno
) lr ON lr.Sector = cr.Sector AND lr.monthno+1 = cr.monthno  
ORDER BY cr.sector, cr.Monthno

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
Exploring Recursive CTEs by Example Dwain Camps

Post #1366952

sayedkhalid99

Posted Tuesday, October 02, 2012 10:53 PM

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i have changed the my input and output and add date and comments to make it clear, for multiple entry with in a month it shall take the last entry.
declare @t table
([id] int,[Amount] int,Sector char(1),Currentdate datetime);
INSERT INTO @t
([id],[Amount],Sector,currentdate )
VALUES
(1, 100,'A','2002-01-01 00:00:00.000'),
(2,50,'A','2002-01-02 00:00:00.000'),
(3, 200,'B','2002-01-01 00:00:00.000'),
(4, 300,'C','2002-01-01 00:00:00.000'),
(5, 400,'A','2002-02-02 00:00:00.000'),
(6, 500,'B','2002-02-02 00:00:00.000'),
(7, 600,'C','2002-02-02 00:00:00.000'),
(8, 100,'A','2002-03-02 00:00:00.000'),
(9, 500,'B','2002-03-03 00:00:00.000'),
(10, 100,'C','2002-03-03 00:00:00.000'),
(11, 200,'C','2002-03-03 00:00:00.000')
select * from @t
declare @output table ([AfterIncreaseDecreaseAmount] int,Amount int,[Monthno]int,sector char(1))
INSERT INTO @output
([AfterIncreaseDecreaseAmount],Amount,[Monthno],sector )
VALUES
(50,100,1,'A'), -- for 01/01/2002 it is 100 , for 02/02/2002 for multiple entry with in the month it shall take the last amount based on max(id) or last(currentdate).
(+350,400,2,'A'), -- for second month 02/02/2002 it 400 > 50 it shows increase from first month so 400-50=+350 so --> AfterIncreaseDecreaseAmount=350
(-300,100,3,'A'), -- for third month 02/03/2002 it is 100 < 400 (sum of 1st,2st month amount) so it shows decrease 100-400=-300 so-->AfterIncreaseDecreaseAmount=-300
(+200,200,1,'B'),-- for b we have 200 it is 200 > 0 ,if it is only one it shall count that as 0 so it shows increase 200-0=200 --> AfterIncreaseDecrease=200
(+300,500,2,'B'),-- for b we have 500 500 > 200--> 500-200=300 it show increased -->AfterIncreaseDecrease=300
(0,500,3,'B'), -- for b in third month 500-500(sum of 1st,2stmonth amount of b) =0 AfterIncreaseDecrease=0
(+300,300,1,'C'),
(+300,600,2,'C'),
(400,100,3,'C')
select * from @output

Post #1367400

ChrisM@Work

Posted Wednesday, October 03, 2012 7:39 AM

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sayedkhalid99 (10/2/2012)

i have changed the my input and output and add date and comments to make it clear, for multiple entry with in a month it shall take the last entry.
....

Please confirm that your desired results are correct for sector C, and add a few extra sample rows for B and C, including multiple rows for a single month. It will aid disambiguation. Thanks.

EDIT: more sample data requested.

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

Post #1367676

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