﻿<?xml version='1.0' encoding='UTF-8'?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/"><channel><title>SQLServerCentral / Administering / SQL Server 2005  / service account / Latest Posts</title><generator>InstantForum.NET v2.9.0</generator><description>SQLServerCentral</description><link>http://www.sqlservercentral.com/Forums/</link><webMaster>notifications@sqlservercentral.com</webMaster><lastBuildDate>Fri, 24 May 2013 13:17:55 GMT</lastBuildDate><ttl>20</ttl><item><title>RE: service account</title><link>http://www.sqlservercentral.com/Forums/Topic626407-146-1.aspx</link><description>Write the services.msc in the run  window, then find out the appropriate service, right click on it, and go to the log on account.</description><pubDate>Mon, 29 Dec 2008 03:15:19 GMT</pubDate><dc:creator>JasKoenig</dc:creator></item><item><title>RE: service account</title><link>http://www.sqlservercentral.com/Forums/Topic626407-146-1.aspx</link><description>Hi Sandhya,You would be able to see the service account details from the "Services.msc" tool. You can reach their by either&amp;gt;&amp;gt; Typing services.msc from run command&amp;gt;&amp;gt; Control panel-&amp;gt; Administrativetools-&amp;gt;ServicesAll the available services are listed with the "startup" type and the "log on as" details. You can check the respective application ( Eg: if its sql server, check for SQL Server and SQL Agent service details to know the service account).If you are not very sure about the respective service name, you can also see the description available on the left hand side for details.-Rajini</description><pubDate>Sun, 28 Dec 2008 22:51:16 GMT</pubDate><dc:creator>rajiniforu</dc:creator></item><item><title>service account</title><link>http://www.sqlservercentral.com/Forums/Topic626407-146-1.aspx</link><description>Hi ,Could any one tell me how to identify under which service acount an application runs.We have an application and iam not able to find out under which service account the app runs.Could any one tell me where exactly to check for the same.Thank You,Regards,Sandhya</description><pubDate>Sun, 28 Dec 2008 22:24:48 GMT</pubDate><dc:creator>sandhyarao49</dc:creator></item></channel></rss>